-2k^2-4=-88

Solution for -2k^2-4=-88 equation:

-2k^2-4=-88

We move all terms to the left:

-2k^2-4-(-88)=0

We add all the numbers together, and all the variables

-2k^2+84=0

a = -2; b = 0; c = +84;
Δ = b2-4ac
Δ = 02-4·(-2)·84
Δ = 672
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{672}=\sqrt{16*42}=\sqrt{16}*\sqrt{42}=4\sqrt{42}$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{42}}{2*-2}=\frac{0-4\sqrt{42}}{-4}
=-\frac{4\sqrt{42}}{-4}
=-\frac{\sqrt{42}}{-1}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{42}}{2*-2}=\frac{0+4\sqrt{42}}{-4}
=\frac{4\sqrt{42}}{-4}
=\frac{\sqrt{42}}{-1}
$